Seoul National University​

SNU Department of Physical Education

Abstract Cause You’re questioned to attract a triangle and all of their perpendicular bisectors and you may angle bisectors

Abstract Cause You’re questioned to attract a triangle and all of their perpendicular bisectors and you may angle bisectors

Question 47. a great. In which sort of triangle can you need to have the fewest segments? What’s the minimum number of segments you might you would like? Explain. b. Where kind of triangle can you have to have the very segments? What is the maximum amount of markets you’d you desire? Describe. Answer:

Matter 48. Thought-provoking The fresh new drawing shows a formal hockey rink used by the Federal Hockey Category. Perform a good triangle using hockey people just like the vertices the spot where the cardio circle is inscribed from the triangle. The heart dot is to he the fresh new incenter of your triangle. Design a drawing of your metropolitan areas of your hockey members. Next title the true lengths of one’s corners in addition to angle steps in your triangle.

Question forty two. You should cut the largest community possible out of an enthusiastic isosceles triangle created from report whose edges try 8 in, twelve in, and you will 12 in. Select the distance of system. Answer:

Concern fifty. To the a map of a go camping. You will want to do a rounded taking walks path you to links the newest pool on (ten, 20), the sort center at (16, 2). and tennis court within (2, 4).

Upcoming solve the difficulty

Answer: The midst of the fresh new rounded road has reached (10, 10) and also the distance of your own circular road was 10 https://datingranking.net/tr/blackplanet-inceleme/ products.

Let the centre of the circle be at O (x, y) Slope of AB = \(\frac \) = 2 The slope of XO must be \(\frac \) the negative reciprocal of the slope of AB as the 2 lines are perpendicular Slope of XO = \(\frac \) = \(\frac \) y – 12 = -0.5x + 3 0.5x + y = 12 + 3 = 15 x + 2y = 30 The slope of BC = \(\frac \) = -3 The slope of XO must be \(\frac \) = \(\frac \) 33 – 3y = 13 – x x – 3y = -33 + 13 = -20 Subtrcat two equations x + 2y – x + 3y = 30 + 20 y = 10 x – 30 = -20 x = 10 r = v(10 – 2)? + (10 – 4)? r = 10

Concern 51. Important Thinking Part D is the incenter out of ?ABC. Write a phrase into length x in terms of the three side lengths Abdominal, Air-con, and you will BC.

Select the coordinates of your own cardiovascular system of your own system while the radius of your system

The endpoints of \(\overline\) are given. Find the coordinates of the midpoint M. Then find AB. Question 52. A(- 3, 5), B(3, 5)

Explanation: Midpoint of AB = (\(\frac \), \(\frac \)) = (0, 5) AB = v(3 + 3)? + (5 – 5)? = 6

Explanation: Midpoint of AB = (\(\frac \), \(\frac \)) = (\(\frac \), -2) AB = v(4 + 5)? + (-5 – 1)? = v81 + 36 =

Build an equation of line passing owing to area P one was perpendicular towards the considering range. Graph brand new equations of one’s lines to check they are perpendicular. Concern 56. P(2, 8), y = 2x + step 1

Explanation: The slope of the given line m = 2 The slope of the perpendicular line M = \(\frac \) The perpendicular line passes through the given point P(2, 8) is 8 = \(\frac \)(2) + b b = 9 So, y = \(\frac \)x + 9

댓글 달기